3x^2-24x+36=180

Solution for 3x^2-24x+36=180 equation:

3x^2-24x+36=180

We move all terms to the left:

3x^2-24x+36-(180)=0

We add all the numbers together, and all the variables

3x^2-24x-144=0

a = 3; b = -24; c = -144;
Δ = b2-4ac
Δ = -242-4·3·(-144)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-48}{2*3}=\frac{-24}{6}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+48}{2*3}=\frac{72}{6}
=12
$